Ta có:
[tex]P=2xy+\sqrt{(x+y)^2-2xy}=2xy+\sqrt{1-2xy}[/tex]
[tex]\Leftrightarrow \frac{P}{\sqrt{2}}=xy\sqrt{2}+\sqrt{(1-2xy).\frac{1}{2}}\leq xy\sqrt{2}+\frac{(1-2xy)+0,5}{2}=xy(\sqrt{2}-1)+0,75\leq \frac{(x+y)^2}{4}(\sqrt{2}-1)+0,75=...[/tex]
Dấu "=" xảy ra khi $x=y=1/2$