Bất Đẳng Thức Cosi

H

hien_vuthithanh

Bạn thấy :2a+2=1−aa+2 \dfrac{2}{a+2}=1-\dfrac{a}{a+2}

TT →2(1a+2+1b+2+1c+2)=3−(aa+2+bb+2+cc+2)\rightarrow 2( \dfrac{1}{a+2}+ \dfrac{1}{b+2}+ \dfrac{1}{c+2}) =3-( \dfrac{a}{a+2}+ \dfrac{b}{b+2}+ \dfrac{c}{c+2})

↔2.1=3−(aa+2+bb+2+cc+2)\leftrightarrow 2.1=3-( \dfrac{a}{a+2}+ \dfrac{b}{b+2}+ \dfrac{c}{c+2})

→aa+2+bb+2+cc+2=1\rightarrow \dfrac{a}{a+2}+ \dfrac{b}{b+2}+ \dfrac{c}{c+2}=1
 
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