bảo toàn khối lượng

L

luffy06041997

n H2 =0.5 mol --> n HCl pư= 2n H2 =1 mol --> n Cl[TEX]^{-}[/TEX]=1 mol --> m muối=m kl + m Cl[TEX]^{-}[/TEX]=20+35.5=55.5g
 
C

chienbg2000

Mg + 2HCl ---> MgCl2 + H2
Fe + 2HCl ---> FeCl2 + H2
ncl- = n hcl=2n h2 =1/2 * 2=1mol
m cl-= 1*35.5=35.5g
m muối = m kl + m cl-= 20 + 35.5=55.5g
 
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