T
theokute


Cho ham so y=1/3x^3-mx^2-3mx +4
tim m de ham so co CĐ,CT tai x1,x2 sao cho :
x1^2+2mx2 +9m)/m^2+m^2/(x2^2+2mx1+9m)=2
tim m de ham so co CĐ,CT tai x1,x2 sao cho :
x1^2+2mx2 +9m)/m^2+m^2/(x2^2+2mx1+9m)=2
Last edited by a moderator: