bài toán Cu

L

lovelycat1994

c.ran sau khi nung: NaOH du va NaNO2.
đặt [TEX]{n}_{NaOH}[/TEX]= x
[TEX]{n}_{NaNO2}[/TEX]=y
ta có hệ: x+y=0,4
40x +69y = 26,44
=> x=0,04: y=0,36
dd X gom: Cu(NO3)2 va HNO3 du.
nN(trong spkhu)= 0,6 - 0,36=0,24
nCu=0,16 => spk: NO
=> nHNO3 pu voi Cu= [TEX]\frac{0,24.4}{3}[/TEX]=0,32
 
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