bài tập phóng xạ

K

king_wang.bbang


$\begin{array}{l}
1(c{m^3}) \to H = 3,923Bq\\
V(c{m^3}) \to H = 3,923V Bq
\end{array}$

Ta có:
$\begin{array}{l}
{H_0} = \lambda {N_0} = \dfrac{{\ln 2}}{{15.3600}}.\dfrac{{{{10}^{ - 13}}}}{{24}}.{N_A} = 32197,1Bq\\
H = {H_0}{2^{\frac{{ - 5}}{{15}}}} = 3,923V\\
\to V = 6514,1c{m^3}
\end{array}$
 
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