ho 4 gam ancol A qua CuO thu duoc 5.6 gam hon hop hoi gom andehit,ruoi du va nuoc.tính hieu suat oxi hoa cua ancol A.ban nao co the noi cho cach lam(de thi thu quoc hoc Hue)
Ptpu:Rch2oh+[o] -->rcho+h2o.btkluongta=>m(o)=5,6-4=1,6g.=>n(o)=0,1=n(ruou)pu.vi ruou du nen Mruou<4:0,1=40=> ruou la ch3oh.ptpu ch3cho + o-->hcho +h2o.vay mruou du=5,6-mhcho-mh2o=0,8....=>hjeu suat pu =80%