bai tap hay day(de thi thu quoc hoc)

H

hocmai.tb

Ptpu:Rch2oh+[o] -->rcho+h2o.btkluongta=>m(o)=5,6-4=1,6g.=>n(o)=0,1=n(ruou)pu.vi ruou du nen Mruou<4:0,1=40=> ruou la ch3oh.ptpu ch3cho + o-->hcho +h2o.vay mruou du=5,6-mhcho-mh2o=0,8....=>hjeu suat pu =80%
 
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