bai hoc sinh gioi hoa 8

T

tien_thientai

Fe3O4 + 8HCl ---> FeCl2 + 2FeCl3 + 4H2O
...0,1........0,8............0,1.......0,2........0,4
nHCl=0,8mol
vây Fe3O4=0,1.232=23,2
mFe+mFe3O4+mTC=100g
mFe+mFe3O4=100.(100%-32%)=68g
vậy mFe=44,8g
 
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