bai hieu suất

P

phuong10a3

T

tvxq289

n hỗn hợp=[TEX]81250(mol)[/TEX]
nbuta-1,3-đien[TEX]=\frac{81250.65}{100}=52812,5(mol)[/TEX]
=> nbuta-1,3-đien phản ứng[TEX]=42250(mol)[/TEX]
[TEX]=> m=42250.54=....(g)[/TEX]
 
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