âxxit nitric

P

pnhn2010

L

levietdung1998

$\begin{array}{l}
NO\\
{n_{echo}} = \frac{{22,4}}{{22,4}}.3 = 0,3\\
{m_{Fe}} = 0,7.{m_{hh}} + 5,6.{n_{echo}} = 10,08\\
\to {m_{hh}} = 12g
\end{array}$
 
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