Câu 1
nNa2CO3=0,15mol ;nKHCO3=0,1mol;nHCl=0,2mol
Na2CO3+HCl->NaCl+NaHCO3
0,15-------0,15
HCO3+H+(dư)->H2O+CO2
0,05---------0,05-------0,05
V=0,05*22,4=1,12(câu D)
Câu 2
nNa2CO3=0,15mol ;nNaHCO3=0,4mol;nHCl=0,42mol
Na2CO3+HCl->NaHCO3+NaCl
0,15---------0,15
HCO3+H+(dư)->H2O+CO2
0,27-------0,27------------0,27
V=0,27*22,4=6,048(Câu A)
Câu 61:
Giả sử có 1 mol KHCO3,x mol CaCO3
2KHCO3->K2CO3+CO2+H2O
1----------0,5
CaCO3->CaO+CO2
x----------x
CaO+H2O->Ca(OH)2
x-------------------x
K2CO3+Ca(OH)2 ->2KOH+CaCO3
x-----------x--------------2x-------x
mCaCO3=100x=(100*1+100x)*0,2=>x=0,25mol
E: KOH(0,5mol) K2CO3(0,25)
KOH+HCl->KCl+H2O
0,5----0,5
K2CO3+HCl->KCl+KHCO3
0,25-----0,25-------------0,25
KHCO3+HCl->KCl+H2O+CO2
0,25-------0,25
Tỉ lệ V:V=0,75:1=3:4(Câu B)
Câu 62:
nH2SO4=nHCl=0,1mol
nNa2CO3=nKHCO3=0,2mol
BTH:nH+=0,3mol
CO3 + H+ ->HCO3-
0,2-----0,2------0,2
HCO3+H+(dư)->CO2 + H2O
0,1-----0,1---------0,1
V=0,1*22,4=2,24l
BTC:nCO3(kt)=0,4-0,1=0,3
BTS:nSO4(kt)=0,1
m=0,1*233+0,3*197=82,4g(Câu C)
Câu III
nHCl=0,35mol
nCO2=0,16mol
Gọi x,y,z lần lượt là số mol CaCO3 , KHCO3 , KCl
100x+100y+74,5z=27,92(1)
CaCO3+2HCl->CaCl2+H2O+CO2
x-----------2x----------x-------------x
KHCO3+HCl->KCl+H2O+CO2
y------------y-------y-------------y
nHCl(dư)=0,35-2x-y
x+y=0,16(2)
(1)(2)=>z=0,16
KCl+AgNO3->KNO3+AgCl
0,16+y--------------------0,16+y
CaCl2+2AgNO3->2AgCl+Ca(NO3)2
x------------------------2x
HCl+AgNO3->AgCl+HNO3
0,35-2x-y--------0,35-2x-y
BT Cl:nAgCl+nHCl+nKCl=0,51
m=0,51*143,5=73,185g