Giải đáp
Câu 6:
[TEX]\\ \\ P \geq \frac{16\sqrt{3}}{xy+yz+zx}+\frac{xy+yz+zx+1}{\sqrt{3+2(xy+yz+zx)}} \\ \\ t=xy+yz+zx,0<t \leq 3 \\ \\ P \geq \frac{16\sqrt{3}}{t}+\frac{t+1}{\sqrt{3+2t}} \\ \\ \Rightarrow minP=\frac{4+16\sqrt{3}}{3} \Leftrightarrow x=y=z=1[/TEX]