200mL dd A: HCl: 0,4 \ mol, \ H_2SO_4: \dfrac{m}{98} \ mol
a) TN1: 25mL dd A => tỷ lệ là \dfrac{25}{200} = \dfrac{1}{8}:
HCl: 0,04 . \dfrac{1}{8} = 0,05 \ mol, \ H_2SO_4: \dfrac{m}{98} . \dfrac{1}{8} = \dfrac{m}{784} \ mol
n_{H_2 \ (TN1)}= \dfrac{1,12}{22,4}=0,05 \ (mol)...