a, Na2O + H2O -> 2NaOH
b, \dpi{100} n_{Na2O} = \frac{15,5}{62} = 0,25 (mol)
Theo ptpứ :
\dpi{100} n_{NaOH} = 2.n_{Na2O}=0,5(mol)
2NaOH + H2SO4 -> Na2SO4 + 2H2O
Theo ptpứ:
\dpi{100} n_{H2SO4}=1/2.n_{NaOH}=0,25 (mol)
\dpi{100} m_{H2SO4}=0,25.98=24,5(g)
\dpi{100} m_{dd...