n_{hh khí}= \frac{3,136}{22,4}=0,14 (mol)
=> n NO= Nsp khử =0,07(mol)
mNO =0,07.30=2,1=> nsp khử= 3,08g => M sp khử = 44 =>N2O
Mg \rightarrow Mg^{2+}+ 2e
x--------------x-----------2x
Al \rightarrow Al^{3+}+ 3e
y.................y..............3y
N^{+5}+3e\rightarrow N^{+2}...