a/ Vrượu = 500.46/100 = 230ml
mrượu = 230.0,8 = 184g
nrượu = 184/46 = 4 mol
=> nC6H12O6 = nCO2 = 2 mol
=> m = 2.180.100/80 = 450g ; V = 2.22.4 = 44,8l
b/ V/10 = 4.48l
=>nCO2 = 0.2 mol
nK+ = 0,2x ; nNa+ = 0,2x ; nOH- = 0,4x
Ta có: 0,2x.39 + 0,2x.23 + 60(0,4x-0,2)+61[0,2-(0,4x-0,2)] = 58,4
=> x =...