PTHH: CuO+H2SO4 -----> CuSO4+H20
n CuO = m/M = 1,6/80 = 0,02 (mol )
m H2SO4 = ( 100.20)/100 = 20 (gam)
n H2SO4 = m/M = 20/98 = 10/49(mol)
chu y : ban nen de so mol la phan so , sau nay tinh khoi luong cho chinh xac
lap PTHH dang du thua
m CUSO4 = 0,02 .160 = 3,2 (gam)
C%=3,2/(1,6+100) =...