nAl2(SO4)3 = 0,1 mol
1 mol thì chứa 6∗1023" role="presentation" style="font-family: "Open Sans", sans-serif; display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">6∗10236∗1023 phân tử
=> 0,1 mol thì chứa x phân tử
x = 0,1∗6∗10231" role="presentation" style="font-family: "Open Sans", sans-serif; display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">0,1∗6∗102310,1∗6∗10231 = 6∗1022" role="presentation" style="font-family: "Open Sans", sans-serif; display: inline; line-height: normal; font-size: 14.6667px; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;">6∗10226∗1022 phân tử
Số phân tử oxi bằng số phân tử Al2(SO4)3
=> nO2 = nAl2(SO4)3 = 0,1 mol
V = 2,24 lít