ksao
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trắc nghiệm à? nhìn là biết C2H5OH rùi
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) nancol =0,1
ancol pu = a
mO = 6,6-4,6 = 2 => nO = 0,125 mol
Có Ancol + 1O--> ADH + H2O
.....x---------->x--------->x
....ancol + 2O --> acid + H2O
....y--------->2y--->y----->y
x+y = a
x+2y = a+y = 0,125=> y = 0,125-a
nH2O = x+y =a
ancol dư = 0,1 -a
naxit + nancol dư + nH2O= 2nH2 =0,15=> 0,125 -a + 0,1 -a + a= 0.15 => a= 0,075
75%
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