

Cho tam giác ABC có ba đướng trung tuyến AI, BJ, CK. Chứng minh rằng
[tex]\underset{AB}{\rightarrow}.\underset{CK}{\rightarrow}+\underset{BC}{\rightarrow}.\underset{AI}{\rightarrow}+\underset{CA}{\rightarrow}.\underset{BJ}{\rightarrow}[/tex] = 0
[tex]\underset{AB}{\rightarrow}.\underset{CK}{\rightarrow}+\underset{BC}{\rightarrow}.\underset{AI}{\rightarrow}+\underset{CA}{\rightarrow}.\underset{BJ}{\rightarrow}[/tex] = 0
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