Giúp mk câu c với !!! Mk cảm ơn
View attachment 173743
Theo câu b có [tex]\frac{AH}{HB}=\frac{HC}{AH}\Leftrightarrow \frac{2AH}{HB}=\frac{2HC}{2MH}\Leftrightarrow \frac{EH}{HC}=\frac{HB}{MH} \Leftrightarrow \frac{EH}{HB}=\frac{HC}{MH}[/tex]
Mà [tex]\widehat{EHB}=\widehat{MHC}=90^{\circ}[/tex]
[tex]\Leftrightarrow \Delta EHB\sim \Delta CHM(c.g.c)\Rightarrow \widehat{HEB}=\widehat{HCM}[/tex]
Có [tex]\widehat{HCM}+\widehat{HMC}=90^{\circ}\Rightarrow \widehat{HCM}+\widehat{KME}=90^{\circ}\Rightarrow \widehat{BEH}+\widehat{KME}=90^{\circ}\Rightarrow \widehat{MKE}=90^{\circ}\Rightarrow CM\perp EB(dpcm)[/tex]