Giải phương trình: [tex]\sqrt{\frac{42}{5-x}}+\sqrt{\frac{60}{7-x}}=6[/tex]
@Mộc Nhãn @iceghost @shorlochomevn@gmail.com @who am i?
[tex]\sqrt{\frac{42}{5-x}}+\sqrt{\frac{60}{7-x}}=6\\\\ <=> \sqrt{\frac{42}{5-x}}-3+\sqrt{\frac{60}{7-x}}-3=0\\\\ <=> \frac{\frac{42}{5-x}-9}{ \sqrt{\frac{42}{5-x}}+3}+\frac{\frac{60}{7-x}-9}{ \sqrt{\frac{60}{7-x}}+3}=0\\\\ <=> \frac{42-45+9x}{(5-x).(\sqrt{\frac{42}{5-x}}+3)}+\frac{60-63+9x}{(7-x).(\sqrt{\frac{60}{7-x}}+3)}=0\\\\ <=> 3.(3x-1).[ \frac{1}{(5-x).(\sqrt{\frac{42}{5-x}}+3)}+\frac{1}{(7-x).(\sqrt{\frac{60}{7-x}}+3)}]=0\\\\ <=> 3x-1=0 <=>...[/tex]