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Giải đáp
$u={x}^{\frac{1}{3}}{(1-x)}^{\frac{2}{3}}$
\Rightarrow $(u)^'=({x}^{\frac{1}{3}})^'{(1-x)}^{\frac{2}{3}}+({(1-x)}^{\frac{2}{3}})^'{x}^{\frac{1}{3}}$
$=\frac{1}{3}{x}^{-\frac{2}{3}}{(1-x)}^{\frac{2}{3}}+\frac{2}{3}{(x-1)}^{-\frac{1}{3}}$
xong nhé ^_6