Violympic9

C

congchuaanhsang

1, $\dfrac{\sqrt{-m^2+4m-4}}{1-m}$=$\dfrac{\sqrt{-(m-2)^2}}{1-m}$

ĐKXĐ $-(m-2)^2$\geq0 và m khác 1 \Leftrightarrow m=2

2, ĐKXĐ x\geq0

\Rightarrow$x+\sqrt{x}$\geq0\Leftrightarrow$x + \sqrt{x} + 1$\geq1
 
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