Viết pttt

N

nguyenbahiep1

[laTEX]I ( -2, 2) \\ \\ M ( x_0,y_0) \\ \\ PTTT: (d): \frac{4}{(x_0+2)^2}.(x-x_0) -y + \frac{2x_0}{x_0+2} \\ \\ d(I ,(d)) = \frac{8}{|x_0+2|.\sqrt{\frac{16}{(x_0+2)^4}+1}} \\ \\ |x_0+2|.\sqrt{\frac{16}{(x_0+2)^4}+1} \geq 2\sqrt{2} \\ \\ \Rightarrow d(I ,(d)) \leq 2\sqrt{2} \\ \\ (x_0+2)^4 = 16 \Leftrightarrow x_0+2 = \pm 2[/laTEX]

từ đây đơn giản rồi
 
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