Viết dưới dạng hiệu hoặc tổng bình phương

C

chaugiang81

$a, (x+y+4)(x+y-4)$
$=(x+y)^2-16$
$b.(x-y+6)(x+y-6)$
$=x^2-(y-6)^2$
$c,( y+2z-3)(y-2z-3)$
$=(y-3)^2-4z^2 $
$d.(x+2y+3z)(2y+3z-x)$
$(2y+3z)^2 -x^2$
 
H

haikhuat2002

a,(x+y+4)(x+y−4)
=(x+y)2−16
b.(x−y+6)(x+y−6)
=x2−(y−6)2
c,(y+2z−3)(y−2z−3)
=(y−3)2−4z2
d.(x+2y+3z)(2y+3z−x)
(2y+3z)2−x2
 
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