[Vật lí 11] Khúc xạ ánh sáng

L

l94

[tex]\frac{sin(r+10^o)}{sinr}=\frac{4}{3} \Leftrightarrow 3sinrcos10^o+3cosrsin10^o=4sinr \Leftrightarrow sinr(3cos10^o-4)=-3cosrsin10^o \Leftrightarrow tanr=\frac{-3sin10^o}{3cos10^o-4} \Rightarrow r[/tex]
 
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