[toán7]Chứng minh

N

nguyenbahiep1

[laTEX]VT = \frac{4-1}{4}.\frac{9-1}{9}......\frac{n^2-1}{n^2} = \frac{(2-1)(2+1)(3-1)(3+1)...(n-1)(n+1)}{2^2.3^2...n^2} \\ \\ VT = \frac{1.2.3^2.4^2....(n-1)^2.n.(n+1)}{2^2.3^2....n^2} = \frac{n+1}{2n} \Rightarrow dpcm[/laTEX]
 
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