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tuongct91


* 8sinx=[tex]\{{sqrt{3}}/cosx }+{1/sinx} * [tex]sin^2x+sinx+cos^3x=0[/tex]
* [tex]\{trac{tan^23x-tan^2x}\{trac{1-tan^23x}{tan^2x}}=1 :)>- [B][COLOR="Red"]bạn vit rõ dề ra, chú ý tiêu dề[/COLOR][/B][/tex]
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