Theo đề ta có:[tex]\frac{1}{c}=\frac{1}{2}(\frac{1}{a}+\frac{1}{}b)[/tex]
=>[tex]\frac{1}{c}:\frac{1}{2}=\frac{1}{a}+\frac{1}{b}[/tex]
=>[tex]\frac{2}{c}=\frac{a}{ab}+\frac{b}{ab}[/tex]
=>[tex]\frac{2}{c}=\frac{a+b}{ab}[/tex]
=>2ab=c(a+b)
=>ab+ab=ac+bc
=>ab-ac=bc-ab
=>a(b-c)=b(a-c)
=>[tex]\frac{a}{b}=\frac{a-c}{b-c}[/tex]
Vậy....