Toán số

N

nguyenbahiep1

[laTEX]5+2\sqrt{6} = \frac{10+4\sqrt{6}}{2} = \frac{(2+\sqrt{6})^2}{2} \\ \\ \Rightarrow \sqrt{5+2\sqrt{6}} = \frac{2+\sqrt{6}}{\sqrt{2}} = \sqrt{2}+\sqrt{3}[/laTEX]

ta có:

[laTEX]6 + \sqrt{24}+\sqrt{12}+\sqrt{8} = (\sqrt{2})^2 + (\sqrt{3})^2 + 1^2 + 2\sqrt{3}.\sqrt{2}+2\sqrt{3}+2\sqrt{2}\\ \\ = (\sqrt{2} +\sqrt{3} +1)^2 [/laTEX]

vậy biểu thức trên = 1
 
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