[Toán số 7] Rút gọn

N

ngocphuong23

A = $\frac{4^5.9^4-2.6^9}{{2}^{10}.3^8+6^8.20}$
= $\frac{{2}^{10}.3^8-{2}^{10}.3^9}{{2}^{10}.3^8+{2}^{10}.3^8.5}$
=$\frac{{2}^{10}.3^8.(1-3)}{{2}^{10}.3^8.(1+5)}$
=$\frac{-2}{6}$=$\frac{-1}{3}$
 
N

nhuquynhdat

$A=\dfrac{4^5 . 9^4 - 2 . 6^9}{2^{10} . 3^8 + 6^8 . 20}$

$A=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10} . 3^8 +2^8.3^8.2^2.5}$

$A=\dfrac{2^{10}.3^8(1-3)}{2^{10}.3^8(1+5)}=\dfrac{-2}{6}=\dfrac{-1}{3}$
 
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