toan p/t khó

N

noinhobinhyen

Ta có : $-x^3+3x-2=-x^3+x^2-x^2+x+2x-2$

$=(x-1)(-x^2-x+2)$

$=(x+2)(x-1)^2$

ĐK $x \leq -2$

$\sqrt[]{4-x} = 2-\sqrt[]{-x^3+3x-2} \leq 2 \Rightarrow x \geq 0$



$\Rightarrow 0 \leq x ; x \leq -2$

Từ đó pt vô nghiệm
 
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