toan p/t khó

N

noinhobinhyen

Ta có : x3+3x2=x3+x2x2+x+2x2-x^3+3x-2=-x^3+x^2-x^2+x+2x-2

=(x1)(x2x+2)=(x-1)(-x^2-x+2)

=(x+2)(x1)2=(x+2)(x-1)^2

ĐK x2x \leq -2

4x=2x3+3x22x0\sqrt[]{4-x} = 2-\sqrt[]{-x^3+3x-2} \leq 2 \Rightarrow x \geq 0



0x;x2\Rightarrow 0 \leq x ; x \leq -2

Từ đó pt vô nghiệm
 
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