Toán nâng cao lớp 8

R

ronaldover7

ta có:
(a+b+c)^2=0 \Rightarrow a^2+b^2+c^2+2(ab+bc+ac)=0
\Rightarrow (a^2+b^2+c^2)^2=[2(ab+bc+ac)]^2
=>a^4+b^4+c^4+2(a^2.b^2+c^2.b^2+a^2.b^2)=4(a^2.b^2+c^2.b^2+a^2.b^2+2abc(a+b+c
=> a^4+b^4+c^4+2(a^2.b^2+c^2.b^2+a^2.b^2)=4(a^2.b^2+c^2.b^2+a^2.b^2)(do a+b+c=0)
=>a^4+b^4+c^4+2(a^2.b^2+c^2.b^2+a^2.b^2)-4(a^2.b^2+c^2.b^2+a^2.b^2)=0

=>a^4+b^4+c^4-2(a^2.b^2+c^2.b^2+a^2.b^2)=0
=>a^4+b^4+c^4=2(a^2.b^2+c^2.b^2+a^2.b^2)
 
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