Toán nâng cao lớp 8 khó

V

vipboycodon

Câu 2:
$VP = \dfrac{2}{1+a}+\dfrac{2}{1+b}+\dfrac{2}{1+c} \le \dfrac{2}{2\sqrt{a}}+\dfrac{2}{2\sqrt{b}}+\dfrac{2}{2\sqrt{c}} = \dfrac{1}{\sqrt{a}}+ \dfrac{1}{\sqrt{b}}+ \dfrac{1}{\sqrt{c}} = \dfrac{\sqrt{ab}+\sqrt{bc}+\sqrt{ac}}{\sqrt{abc}} \le a+b+c = VT$
 
Top Bottom