a)($125^{3}$. $7^{4}$-$5^{9}$.$49^{2}$):$2005^{2006}$
= ($5^{9}$. $7^{4}$-$5^{9}$.$7^{4}$):$2005^{2006}$
= 0 : $2005^{2006}$ =0

b) $64^{2}$.$81^{2}$.34: ($2^{13}$.$3^{9}$.17)
= $2^{12}$.$3^{12}$.2.17:$2^{13}$:$3^{9}$:17
= $2^{13}$.$3^{12}$.17:$2^{13}$:$3^{9}$:17
= $3^{12}$:$3^{9}=$3^{3} /

c) 16.64.$8^{2}$: ($4^{3}$.$2^{5}$.16)
= 16.$4^{3}$.$2^{6}$:$4^{3}$:$2^{5}$:16
= $2^{6}$:$2^{5}$=2

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