toán lop 8

H

huuthuyenrop2

Câu a nhé,
$\dfrac{41.66+41.34}{3+7+11+....+79} = \dfrac{41.(66+34)}{820} = \dfrac{4100}{820} = 5$
Câu b,
$\dfrac{1+2+3+..+200}{6+8+10+.....+34} = \dfrac{20100}{300} = 67$
 
H

huy14112

$C = \dfrac{{1.5.6 + 2.10.12 + 4.20.24 + 9.45.54}}{{1.3.5 + 2.6.10 + 4.12.20 + 9.27.45}}$

$C = \dfrac{{2.(1.3.5 + 2.6.10 + 4.12.20 + 9.27.45)}}{{1.3.5 + 2.6.10 + 4.12.20 + 9.27.45}}=2$
 
Top Bottom