toán lớp 6 nè

D

darknightmath

S

supperdragon9510

a)1/5.8+1/8.11+1/11.14+...+1/x.(x+3)=101/1540
1/(5.8)+1/(8.11)+1/(11.14)+...1/x.(… =101/1540
3/(5.8)+3/(8.11)+...+3/x(x+3)=3.(10…
1/5-1/8+1/8-1/11+...+1/x-1/(x+3)=30…
1/5-1/(x+3)=303/1540
1/(x+3)=1/5-303/1540=1/308
\Rightarrowx=305
b)1 + 1/3 + 1/6 + 1/10 + ... + 1/[n(n+1)/2] = 3984/1993
1/2 + 1/6 + 1/12 + 1/20 + ... + 1/[n(n+1)] = 1992/1993
1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + ... + 1/n - 1/(n+1) = 1992/1993
1 - 1/(n+1) = 1992/1993 ---> n/(n+1) = 1992/1993
\Rightarrown = 1992.
 
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