T
thuytrangnbk20


Tìm a, b, c biết:
A = ($\dfrac{1}{a^2}$+1)($\dfrac{1}{b^2}$+2)($\dfrac{1}{c^2}$+8) = $\dfrac{32}{abc}$
A = ($\dfrac{1}{a^2}$+1)($\dfrac{1}{b^2}$+2)($\dfrac{1}{c^2}$+8) = $\dfrac{32}{abc}$