toán khó

P

petercat

ta có:
$\sqrt{\sqrt{3}-x}$= x$\sqrt{\sqrt{3}+x}$
\Leftrightarrow$\sqrt{3}-x$=Sx^2.\sqrt{3}$+x
\Leftrightarrow$x^2+2x$=0
\Leftrightarrowx(x+2)=0
\Leftrightarrowx=0 ; x=-2
 
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