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Q

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[TEX]A=\frac{1}{199}+\frac{2}{198}+\frac{3}{197}+...+ \frac{198}{2}+\frac{199}{1}[/TEX]
\Rightarrow[TEX]A+199=\frac{1}{199}+1+\frac{2}{198}+1+\frac{3}{197}+1+..+\frac{198}{2}+1+\frac{199}{1}+1[/TEX]
[TEX]A+199=\frac{200}{199}+\frac{200}{198}+...+200=200( \frac{1}{2}+\frac{1}{3}+ \frac{1}{4} +...+\frac{1}{200})+199[/TEX]
[TEX]A=200(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+ \frac{1}{200})[/TEX]
 
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