Ta có [tex]\widehat{B}+\widehat{C}=90[/tex]
=> sinB=cosC=[tex]\frac{1}{4}[/tex]
=>[tex]cos^{2}C=\frac{1}{16}[/tex]
=>[tex]sin^2C=1-\frac{1}{16}=\frac{15}{16}[/tex]
Mà [tex]tg^2C=\frac{sin^2C}{cos^2C}[/tex]
=>[tex]tg^2C=\frac{15}{16}:\frac{1}{16}=15[/tex]
=>[tex]tgC=\sqrt{15}[/tex]