toán hình giải gấp !!!

T

trinhminh18

ta có : $\dfrac{SIMB}{SABM}$=$\dfrac{SIMC}{SAMC}$=$\dfrac{IM}{AM}$
\Rightarrow$\dfrac{SIMB+SIMC}{SABC}$=$\dfrac{IM}{AM}$
\Rightarrow$\dfrac{SIBC}{SABC}$=$\dfrac{IM}{AM}$
C/m tuong tu đc:
$\dfrac{SAIB}{SABC}$=$\dfrac{EI}{IC}$
$\dfrac{SAIC}{SABC}$=$\dfrac{IN}{NB}$
\Rightarrow$\dfrac{IM}{AM}$+$\dfrac{EI}{IC}$+ $\dfrac{IN}{NB}$=$1$
 
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