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$\rightarrow 8 \widehat{A}=12 \widehat{B} = 15 \widehat{C}$

$\rightarrow \dfrac{\widehat{A}}{15}=\dfrac{\widehat{B}}
{10}=\dfrac{\widehat{C}}{8}=\dfrac{\widehat{180^o}}{33}=5^o27'$

$\rightarrow$ $\widehat{A} \approx 81^o49' \\ \widehat{B} \approx 54^o33'
\\ \widehat{C} \approx 43^ỏ8'$


 
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