Toán hhay đê

P

perfectday8

a) $ 1^2 - 2^2 + 3^2 - 4^2 + ... + 2011^2 - 2012^2 \\
= (1-2)(1+2) + (3-4)(3+4) + ... + (2011-2012)(2011+2012) \\
= - 3 -7 -11 -15 -... - 4023 \\
= \sum \limits_{n=1}^{1006} (1 - 4n) $
Vì $ 1 + 2 + 3 + ... + n = \frac{n(n+1)}{2} $
nên $ \sum \limits_{n=1}^{1006} (1 - 4n) = 1006 - 4 \frac{1006 \times 1007}{2} = -2025078 $

b) $ (85^2 - 15^2) + (75^2 - 25^2) + (65^2 - 35^2) + (55^2 - 45^2) \\
= 100 \times (70 + 50 + 30 + 10) = 16000 $
 
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