toán đề cương lớp 7

T

thuyluypuy

(bz-cy)/a = (cx-az)/b = (ay-bx)/c
\Rightarrow (bzx-cyx)/ax = (cxy-azy)/by = (ayz-bxz)/cz
= (bzx-cyx+cxy-azy+ayz-bxz)/(ax+by+cz)
= 0/(ax+by+cz) = 0
\Rightarrow bz=cy \Rightarrow z/c = y/b
cx=az \Rightarrow x/a = z/c
Vậy x/a = y/b = z/c
 
Last edited by a moderator:
You must log in or register to reply here.
Top Bottom