toan dai so 9 day

K

khang9988

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V

v0_danh

So sánh:
A= [tex]\frac{1}{\sqrt[]{2005.1} }[/tex] + [tex]\frac{1}{\sqrt[]{2004.2}}[/tex] + [tex]\frac{1}{\sqrt[]{2003.3}}[/tex] +......+ [tex]\frac{1}{\sqrt[]{1.2005}}[/tex]

B=[tex]\frac{2005}{1003}[/tex]

A>B vì
2(A= [tex]\frac{1}{\sqrt[]{2005.1} }[/tex] + [tex]\frac{1}{\sqrt[]{2004.2}}[/tex] + [tex]\frac{1}{\sqrt[]{2003.3}}[/tex] +......+ [tex]\frac{1}{\sqrt[]{1.2005}}[/tex])

\Rightarrow căn2005<1003
\Leftrightarrow1/1003<1/căn(2005.1)
 
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