Toán Đại 8 (chương I+II)

N

ngochuongptnh

M

minhhieupy2000

3

3/ $x^4-34x^2+225$$=x^4-25x^2-9x^2+225=(x^2-25)x^2-9(x^2-25)=(x^2-25)(x^2-9)=(x-3)(x-5)(x+3)(x+5)$
 
M

minhhieupy2000

1

Ta có :
$\dfrac{x+1}{x^6+1}=\dfrac{x+1}{(x^2)^3+1}=\dfrac{(x+1)x}{(x^2+1)(x^4-x^2+1)x}$
$\dfrac{x^2-1}{x^5-x^3+x}=\dfrac{(x^2+1)(x^2-1)}{x(x^2+1)(x^4-x^2+1)}$
 
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