C
chibisuka_256
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Cho n thuộc N ( sao ), Chứng minh
a)[\frac{a}{b}] (a=n,b=2)+[\frac{a}{b}] (a=n+1, b=2) = n
b)[\frac{a}{b}] (a=[a], b=n) = [\frac{a}{b}] (a=a,b=n)
a)[\frac{a}{b}] (a=n,b=2)+[\frac{a}{b}] (a=n+1, b=2) = n
b)[\frac{a}{b}] (a=[a], b=n) = [\frac{a}{b}] (a=a,b=n)
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